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Dear Seachem
A few days ago I got the chance to purchase a set of Seachem alkaline and acid buffer for my freshwater aquarium and couldn't be any more happy. After reading the instructions on each buffer everything seems quite straight forward but there's just one question I'd like to ask is to finding out the math formula to calculate how many grams of each buffer I need to add to get the right dKH.
Alkaline buffer instruction
To increase pH, use 1 teaspoon (6 g) for every 80 L (20 gallons) daily until desired pH is reached (this dose raises alkalinity by about 1 meq/L (2.8 dKH))
Acid buffer instructions
To lower pH, use 1/4 teaspoon (2g) for every 80 L (20 US gallons) daily until desired pH is reached (this dose lowers alkalinity by about 0.2 meq/L (0.6 dKH))
Currently I'm trying to get a ph of 7 and a dKH of 7 in a 5 gallon bucket of RO water. It mentions I need ratio of 2/1 of alkaline & acid buffer to get a ph of 7. But now I'm confused on the part on how to find out the right amount to add in order to get the desired dKH, please correct me if my math is wrong.
Since the ratio for the PH is 2 to 1, i need to change the change the instruction dosage from 6g of alkaline buffer to 4g instead since I'll be taking the acid buffer instruction of 2g into account.
6/4g = 2.8dkh/x x=1.866dkh
So assuming I'm making sense 4g of alkaline buffer for every 20 gallon will increase alkalinity by 1.866kh
Then for everyone 4g of alkaline buffer i'll be adding 2g of acid buffer, assuming I'm not wrong, I'll need to take the 1.866kh and minus it by .6dkh, leading to a increase in 1.266dkh for every 4g-alkaline/2g-acid buffer I add into a 20 gallon container.
Then to to achieve a dKH of 7, I'll need to divide 7 by 1.266 = 5.53 doses of 4/2g of alkaline/acid buffer
But then since I'll be using a 5gallon bucket instead of dosing for 20 gallons I should divide 5.53 doses by 4 = 1.38 dose of 4/2g of alkaline/acid buffer
Then a dose of 1.38 x 4g = 5.52g of alkaline buffer
1.38 x 2g = 2.76g of acid buffer
Not sure am I right or wrong or making any logical sense but is 5.52g of alkaline and 2.76g of acid buffer the right amount to get a 5 gallon bucket of RO water to 7ph and 7dKH? Sorry my awkward tone and many thanks in advance.
A few days ago I got the chance to purchase a set of Seachem alkaline and acid buffer for my freshwater aquarium and couldn't be any more happy. After reading the instructions on each buffer everything seems quite straight forward but there's just one question I'd like to ask is to finding out the math formula to calculate how many grams of each buffer I need to add to get the right dKH.
Alkaline buffer instruction
To increase pH, use 1 teaspoon (6 g) for every 80 L (20 gallons) daily until desired pH is reached (this dose raises alkalinity by about 1 meq/L (2.8 dKH))
Acid buffer instructions
To lower pH, use 1/4 teaspoon (2g) for every 80 L (20 US gallons) daily until desired pH is reached (this dose lowers alkalinity by about 0.2 meq/L (0.6 dKH))
Currently I'm trying to get a ph of 7 and a dKH of 7 in a 5 gallon bucket of RO water. It mentions I need ratio of 2/1 of alkaline & acid buffer to get a ph of 7. But now I'm confused on the part on how to find out the right amount to add in order to get the desired dKH, please correct me if my math is wrong.
Since the ratio for the PH is 2 to 1, i need to change the change the instruction dosage from 6g of alkaline buffer to 4g instead since I'll be taking the acid buffer instruction of 2g into account.
6/4g = 2.8dkh/x x=1.866dkh
So assuming I'm making sense 4g of alkaline buffer for every 20 gallon will increase alkalinity by 1.866kh
Then for everyone 4g of alkaline buffer i'll be adding 2g of acid buffer, assuming I'm not wrong, I'll need to take the 1.866kh and minus it by .6dkh, leading to a increase in 1.266dkh for every 4g-alkaline/2g-acid buffer I add into a 20 gallon container.
Then to to achieve a dKH of 7, I'll need to divide 7 by 1.266 = 5.53 doses of 4/2g of alkaline/acid buffer
But then since I'll be using a 5gallon bucket instead of dosing for 20 gallons I should divide 5.53 doses by 4 = 1.38 dose of 4/2g of alkaline/acid buffer
Then a dose of 1.38 x 4g = 5.52g of alkaline buffer
1.38 x 2g = 2.76g of acid buffer
Not sure am I right or wrong or making any logical sense but is 5.52g of alkaline and 2.76g of acid buffer the right amount to get a 5 gallon bucket of RO water to 7ph and 7dKH? Sorry my awkward tone and many thanks in advance.
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